My LeetCode Diary - Day51 Dynamic Programming
309. Best Time to Buy and Sell Stock with Cooldown
Link
class Solution {
public int maxProfit(int[] prices) {
int n = prices.length;
int[][] dp = new int[n][2];
for (int i = 0; i < n; i++) {
if (i-1 == -1 ) {
dp[i][0] = 0;
dp[i][1] = -prices[i];
continue;
}
if (i-2 == -1) {
dp[i][0] = Math.max(dp[i-1][0], dp[i-1][1] + prices[i]);
dp[i][1] = Math.max(dp[i-1][1], - prices[i]);
continue;
}
dp[i][0] = Math.max(dp[i-1][0],dp[i-1][1]+prices[i]);
dp[i][1] = Math.max(dp[i-1][1],dp[i-2][0]-prices[i]);
}
return dp[n-1][0];
}
}
714. Best Time to Buy and Sell Stock with Transaction Fee
Link
class Solution {
public int maxProfit(int[] prices, int fee) {
int n = prices.length;
int[][] dp = new int[n][2];
dp[0][0] = 0;
dp[0][1] = -prices[0]-fee;
for (int i = 1; i < n; i++) {
dp[i][0] = Math.max(dp[i-1][0], dp[i-1][1] + prices[i]);
dp[i][1] = Math.max(dp[i-1][1], dp[i-1][0] - prices[i]-fee);
}
return dp[n-1][0];
}
}