My LeetCode Diary - Day48 Dynamic Programming

198. House Robber

Link

class Solution {
	public int rob(int[] nums) {
		if (nums == null || nums.length == 0) return 0;
		if (nums.length == 1) return nums[0];

		int[] dp = new int[nums.length];
		dp[0] = nums[0];
		dp[1] = Math.max(dp[0], nums[1]);
		for (int i = 2; i < nums.length; i++) {
			dp[i] = Math.max(dp[i - 1], dp[i - 2] + nums[i]);
		}

		return dp[nums.length - 1];
	}
}

213. House Robber II

Link

class Solution {
    public int rob(int[] nums) {
        if (nums == null || nums.length == 0)
            return 0;
        int len = nums.length;
        if (len == 1)
            return nums[0];
        return Math.max(robAction(nums, 0, len - 1), robAction(nums, 1, len));
    }

    int robAction(int[] nums, int start, int end) {
        int x = 0, y = 0, z = 0;
        for (int i = start; i < end; i++) {
            y = z;
            z = Math.max(y, x + nums[i]);
            x = y;
        }
        return z;
    }
}

337. House Robber III

Link

class Solution {
    public int rob(TreeNode root) {
        int[] res = robAction1(root);
        return Math.max(res[0], res[1]);
    }

    int[] robAction1(TreeNode root) {
        int res[] = new int[2];
        if (root == null)
            return res;

        int[] left = robAction1(root.left);
        int[] right = robAction1(root.right);

        res[0] = Math.max(left[0], left[1]) + Math.max(right[0], right[1]);
        res[1] = root.val + left[0] + right[0];
        return res;
    }
    
}