My LeetCode Diary - Day48 Dynamic Programming
198. House Robber
Link
class Solution {
public int rob(int[] nums) {
if (nums == null || nums.length == 0) return 0;
if (nums.length == 1) return nums[0];
int[] dp = new int[nums.length];
dp[0] = nums[0];
dp[1] = Math.max(dp[0], nums[1]);
for (int i = 2; i < nums.length; i++) {
dp[i] = Math.max(dp[i - 1], dp[i - 2] + nums[i]);
}
return dp[nums.length - 1];
}
}
213. House Robber II
Link
class Solution {
public int rob(int[] nums) {
if (nums == null || nums.length == 0)
return 0;
int len = nums.length;
if (len == 1)
return nums[0];
return Math.max(robAction(nums, 0, len - 1), robAction(nums, 1, len));
}
int robAction(int[] nums, int start, int end) {
int x = 0, y = 0, z = 0;
for (int i = start; i < end; i++) {
y = z;
z = Math.max(y, x + nums[i]);
x = y;
}
return z;
}
}
337. House Robber III
Link
class Solution {
public int rob(TreeNode root) {
int[] res = robAction1(root);
return Math.max(res[0], res[1]);
}
int[] robAction1(TreeNode root) {
int res[] = new int[2];
if (root == null)
return res;
int[] left = robAction1(root.left);
int[] right = robAction1(root.right);
res[0] = Math.max(left[0], left[1]) + Math.max(right[0], right[1]);
res[1] = root.val + left[0] + right[0];
return res;
}
}